Preguntes
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When "Delete Record" set doesn't have index what it is going to delete while debugging ??
Delete Record input doesn't have index.
but when I debug It is showing the message as success so here actually what is deleting by the Delete Record ??
At least when I debug it should show some message as record set doesn't exist.
but when I debug It is showing the message as success so here actually what is deleting by the Delete Record ??
At least when I debug it should show some message as record set doesn't exist.
Answer
Answer
Respost
Hi Murali
If the recordset is being used as an Input and does not have an index specified [[rec().set]], then it will use the last record.
If the recordset is being used as an Output and does not have an index specified [[rec().set]], then it will add a new record.
So in your example above, the last record in the recordset was deleted. The debug output should show you the record number.
There is a Warewolf Language Help button at the top of the studio:
It has more detail on how the language works.
If the recordset is being used as an Input and does not have an index specified [[rec().set]], then it will use the last record.
If the recordset is being used as an Output and does not have an index specified [[rec().set]], then it will add a new record.
So in your example above, the last record in the recordset was deleted. The debug output should show you the record number.
There is a Warewolf Language Help button at the top of the studio:
It has more detail on how the language works.
Customer support service by UserEcho
If the recordset is being used as an Input and does not have an index specified [[rec().set]], then it will use the last record.
If the recordset is being used as an Output and does not have an index specified [[rec().set]], then it will add a new record.
So in your example above, the last record in the recordset was deleted. The debug output should show you the record number.
There is a Warewolf Language Help button at the top of the studio:
It has more detail on how the language works.